Running Linpack

Yoon Jae Ho yoon at bh.kyungpook.ac.kr
Thu Jun 28 19:35:09 EDT 2001


please refer,

http://www.phy.duke.edu/brahma/blas

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Yoon Jae Ho
Economist
POSCO Research Institute
 
yoon at bh.kyungpook.ac.kr
jhyoon at mail.posri.re.kr
http://ie.korea.ac.kr/~supercom/  Korea Beowulf Supercomputer
http://members.ud.com/services/teams/team.htm?id=264C68D5-CB71-429F-923D-8614F419065D     Help the people with your PC 
 
Imagination is more important than knowledge.  A. Einstein
http://www.kichun.co.kr   2001.1.6
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----- Original Message ----- 
From: Felix Rauch <rauch at inf.ethz.ch>
To: Ferdinand Mahr <MAHRF at de.ibm.com>
Cc: <beowulf at beowulf.org>
Sent: Thursday, June 28, 2001 11:55 PM
Subject: Re: Running Linpack


> On Thu, 28 Jun 2001, Ferdinand Mahr wrote:
> > Has anyone experience with the High Performance Linpack benchmark from
> > netlib.org? After some trouble with the makefiles, I was able to compile
> > and run it on a dual machine (unfortunately I don't have two seperate
> > similar machines or even a cluster at work right now), but when it finished
> > after an hour or so, I didn't get any results.
> > My question is: how can I determine the MFLOP performance of my system
> > (compareable to the results in the top500.org list)? I couldn't find an
> > answer in the provided documentation. Is there a script that analyzes the
> > output of the program? Are there any other linpack benchmark
> > implementations?
> 
> On the standard output (or your output file) you should see something
> like this:
> 
> T/V                N    NB     P     Q               Time             Gflops
> ----------------------------------------------------------------------------
> W01R2L8        57000    94     8    16            2212.04          5.582e+01
> ----------------------------------------------------------------------------
> ||Ax-b||_oo / ( eps * ||A||_1  * N        ) =        0.0013793 ...... PASSED
> ||Ax-b||_oo / ( eps * ||A||_1  * ||x||_1  ) =        0.0017576 ...... PASSED
> ||Ax-b||_oo / ( eps * ||A||_oo * ||x||_oo ) =        0.0003179 ...... PASSED
> 
> My understanding is that the number below Gflops is the achieved
> performance.
> 
> If you specified multiple runs, you will see multiple outputs of the
> above. Choose the highest number with all operations "PASSED" (nothing
> "FAILED").
> 
> - Felix
> -- 
> Felix Rauch                      | Email: rauch at inf.ethz.ch
> Institute for Computer Systems   | Homepage: http://www.cs.inf.ethz.ch/~rauch/
> ETH Zentrum / RZ H18             | Phone: ++41 1 632 7489
> CH - 8092 Zuerich / Switzerland  | Fax:   ++41 1 632 1307
> 
> 
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